The request

From Daniel Brooks, Head of Operations
Your goal
Set result to a Series of the mean shipping_fee per channel, rounded to 2 decimals, as returned by orders.groupby("channel")["shipping_fee"].mean(): index = channel (sorted A to Z), values named shipping_fee.
- Use the
ordersDataFramenot done yet - Show exactly
channelshipping_feenot done yet - 3 rows, sorted as askednot done yet
Your code
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Reference solution
| order_id | customer_id | order_date | status | channel |
|---|---|---|---|---|
| 1001 | 125 | 2023-01-01 20:51:19 | completed | web |
| 1002 | 156 | 2023-01-02 07:58:46 | completed | web |
| 1003 | 22 | 2023-01-02 10:25:27 | completed | marketplace |
| 1004 | 48 | 2023-01-02 11:21:51 | completed | marketplace |
Mote checks your result
Press Run. Each row that matches the goal becomes a firefly in your lantern.
What Daniel gets, and why
DataFrames
Loaded for you as pandas DataFrames, plus pd and np.
orders12,000 rows · 7 columns
order_idintegercustomer_idintegerorder_datetimestampstatusvarcharchannelvarcharshipping_feedecimalcoupon_codevarchar
| order_id | customer_id | order_date | status | channel | shipping_fee | coupon_code |
|---|---|---|---|---|---|---|
| 1001 | 125 | 2023-01-01 20:51:19 | completed | web | 0.00 | NaN |
| 1002 | 156 | 2023-01-02 07:58:46 | completed | web | 0.00 | NaN |
| 1003 | 22 | 2023-01-02 10:25:27 | completed | marketplace | 4.99 | WELCOME10 |
| 1004 | 48 | 2023-01-02 11:21:51 | completed | marketplace | 4.99 | WELCOME10 |
| 1005 | 82 | 2023-01-02 11:43:36 | completed | web | 0.00 | WELCOME10 |
customers2,018 rows · 9 columns
customer_idintegerfirst_namevarcharlast_namevarcharemailvarcharcityvarcharstatevarcharsignup_datedatesegmentvarcharreferral_sourcevarchar
| customer_id | first_name | last_name | city | state | signup_date | segment | referral_source | |
|---|---|---|---|---|---|---|---|---|
| 1 | Owen | Hudson | owen.hudson@icloud.com | San Francisco | CA | 2022-06-02 | consumer | search |
| 2 | Douglas | Mendoza | dmendoza69@gmail.com | Atlanta | GA | 2022-06-02 | consumer | NaN |
| 3 | Henry | Brooks | hbrooks@lakesidecafe.com | Los Angeles | CA | 2022-06-04 | business | NaN |
| 4 | Brian | Graham | bgraham@bluecedarhomes.com | Seattle | WA | 2022-06-06 | business | |
| 5 | Kyle | Jimenez | kjimenez27@yahoo.com | Indianapolis | IN | 2022-06-07 | consumer | NaN |
products120 rows · 8 columns
product_idintegernamevarcharcategoryvarcharsubcategoryvarcharunit_pricedecimalunit_costdecimallaunched_ondateis_activeboolean
| product_id | name | category | subcategory | unit_price | unit_cost | launched_on | is_active |
|---|---|---|---|---|---|---|---|
| 101 | Vale Velvet Loveseat | Furniture | Sofas | 1659.00 | NaN | 2023-09-11 | true |
| 102 | Alder Oak Coffee Table | Furniture | Tables | 919.00 | 503.50 | 2024-05-16 | true |
| 103 | Orchard Rattan Dining Chair | Furniture | Chairs | 789.00 | 429.87 | 2023-05-27 | true |
| 104 | Upland Oak Bookcase | Furniture | Storage | 429.00 | 214.70 | 2022-12-20 | true |
| 105 | Avery Leather Bed Frame | Furniture | Beds | 449.00 | 232.70 | 2021-08-31 | true |
order_items30,338 rows · 6 columns
order_item_idintegerorder_idintegerproduct_idintegerquantityintegerunit_pricedecimaldiscount_pctdecimal
| order_item_id | order_id | product_id | quantity | unit_price | discount_pct |
|---|---|---|---|---|---|
| 1 | 1001 | 121 | 9 | 31.99 | 0.00 |
| 2 | 1001 | 154 | 3 | 11.99 | 0.00 |
| 3 | 1002 | 154 | 4 | 11.99 | 0.00 |
| 4 | 1002 | 194 | 1 | 149.00 | 0.00 |
| 5 | 1002 | 193 | 2 | 19.99 | 0.00 |
returns1,673 rows · 5 columns
return_idintegerorder_item_idintegerreturned_ondatereasonvarcharrefund_amountdecimal
| return_id | order_item_id | returned_on | reason | refund_amount |
|---|---|---|---|---|
| 1 | 14 | 2023-01-10 | damaged | 83.69 |
| 2 | 42 | 2023-01-10 | wrong_item | 19.99 |
| 3 | 105 | 2023-01-14 | wrong_item | 10.99 |
| 4 | 24 | 2023-01-16 | changed_mind | 26.99 |
| 5 | 126 | 2023-01-16 | late | 20.99 |
employees60 rows · 8 columns
employee_idintegerfirst_namevarcharlast_namevarchardepartmentvarchartitlevarcharmanager_idintegerhire_datedatesalaryinteger
| employee_id | first_name | last_name | department | title | manager_id | hire_date | salary |
|---|---|---|---|---|---|---|---|
| 1 | Catherine | Hale | Executive | Chief Executive Officer | NaN | 2016-03-01 | 285000 |
| 2 | Robert | Kim | Executive | Chief Operating Officer | 1 | 2017-01-09 | 235000 |
| 3 | Megan | Collins | Sales | Head of Sales | 1 | 2018-04-16 | 172000 |
| 4 | Chloe | Gutierrez | Sales | Account Executive | 3 | 2020-01-21 | 72000 |
| 5 | Frank | Bell | Sales | Account Executive | 3 | 2023-05-21 | 73000 |
web_sessions40,000 rows · 7 columns
session_idintegercustomer_idintegerstarted_attimestampdevicevarcharsourcevarcharpages_viewedintegerconvertedboolean
| session_id | customer_id | started_at | device | source | pages_viewed | converted |
|---|---|---|---|---|---|---|
| 1 | NaN | 2023-01-01 23:02:24 | mobile | paid | 1 | false |
| 2 | 18 | 2023-01-01 15:07:49 | desktop | paid | 1 | false |
| 3 | NaN | 2023-01-01 16:55:46 | desktop | direct | 7 | false |
| 4 | NaN | 2023-01-01 12:43:28 | mobile | organic | 3 | false |
| 5 | NaN | 2023-01-01 13:06:21 | mobile | social | 2 | false |
marketing_spend3,276 rows · 3 columns
spend_datedatechannelvarcharamountdecimal
| spend_date | channel | amount |
|---|---|---|
| 2023-01-01 | paid | 492.99 |
| 2023-01-01 | 37.38 | |
| 2023-01-01 | social | 200.53 |
| 2023-01-02 | paid | 709.13 |
| 2023-01-02 | 64.13 |
The lesson
Split, apply, combine
groupby does three things in one call:
- Split the rows into groups that share a value (one group per channel).
- Apply a calculation to each group (the mean shipping fee).
- Combine the answers into a new Series or DataFrame, one row per group.
orders.groupby("channel")["shipping_fee"].mean()
channel
app ...
marketplace ...
web ...
Name: shipping_fee, dtype: float64
Read it left to right: group orders by channel, take the shipping_fee column, average it. The group keys become the index of the result, sorted A to Z by default.
Common aggregations
| method | per group |
|---|---|
.sum() |
total |
.mean() / .median() |
average / middle value |
.min() / .max() |
extremes |
.count() |
non-missing values in the column |
.size() |
rows, missing or not |
.nunique() |
distinct values |
count and size look alike but answer different questions:
orders.groupby("channel")["coupon_code"].count() # orders WITH a coupon, per channel
orders.groupby("channel").size() # all orders, per channel
count skips missing values, so it’s a count of coupons used. size counts rows. Mixing them up
produces numbers that look plausible and are wrong, which is the worst kind.
Series or DataFrame?
Selecting one column after groupby gives a Series indexed by the group. To get an ordinary
two-column table, which is usually what you want for display, merging or export, use
reset_index() or as_index=False:
orders.groupby("channel")["shipping_fee"].mean().reset_index()
orders.groupby("channel", as_index=False)["shipping_fee"].mean()
Both give a DataFrame with columns channel and shipping_fee.
Reading the result
The average fee per channel mixes free-shipping orders (fee 0) with paid ones. That’s a fair answer to “what does shipping bring in per order?”, but not to “what do people pay when they pay?”. For the second question, filter first:
paid = orders[orders["shipping_fee"] > 0]
paid.groupby("channel")["shipping_fee"].mean()
Same code, different rows, different meaning. Always ask which population the question is about before you group.
Sorting the output
The result is sorted by the group key. To rank groups by the value instead, sort afterwards:
.sort_values(ascending=False).
Common mistakes
- Forgetting to select a column:
orders.groupby("channel").mean()tries to average every column and fails on text columns in pandas 2. Select what you need, or passnumeric_only=True. - Using
count()when you mean “number of rows”. - Comparing averages without the group sizes. A channel with few orders can have an extreme mean
by chance; show
size()alongside.
If you know SQL
This is SELECT channel, AVG(shipping_fee) FROM orders GROUP BY channel.
Lantern lit!
Practised: groupbymeansizecountsplit apply combine
- Solved
- No hints
- First run
