1. Lighthouse

Level 2 · Average shipping fee per channel

The request

From Daniel Brooks, Head of Operations

“Marketplace orders seem to pay different shipping than our own site and app. What's the average shipping fee per channel, across all orders?”

Your goal

Set result to a Series of the mean shipping_fee per channel, rounded to 2 decimals, as returned by orders.groupby("channel")["shipping_fee"].mean(): index = channel (sorted A to Z), values named shipping_fee.

  • Use the orders DataFramenot done yet
  • Show exactly channel shipping_feenot done yet
  • 3 rows, sorted as askednot done yet

Your code

Python

Loading the editor…

    ResultPreview of orders · press Run to see yours
    Preview of orders
    order_idcustomer_idorder_datestatuschannel
    10011252023-01-01 20:51:19completedweb
    10021562023-01-02 07:58:46completedweb
    1003222023-01-02 10:25:27completedmarketplace
    1004482023-01-02 11:21:51completedmarketplace

    Mote checks your result

    Press Run. Each row that matches the goal becomes a firefly in your lantern.

    DataFrames

    Loaded for you as pandas DataFrames, plus pd and np.

    orders12,000 rows · 7 columns
    • order_idinteger
    • customer_idinteger
    • order_datetimestamp
    • statusvarchar
    • channelvarchar
    • shipping_feedecimal
    • coupon_codevarchar
    First 5 rows of orders
    order_idcustomer_idorder_datestatuschannelshipping_feecoupon_code
    10011252023-01-01 20:51:19completedweb0.00NaN
    10021562023-01-02 07:58:46completedweb0.00NaN
    1003222023-01-02 10:25:27completedmarketplace4.99WELCOME10
    1004482023-01-02 11:21:51completedmarketplace4.99WELCOME10
    1005822023-01-02 11:43:36completedweb0.00WELCOME10
    customers2,018 rows · 9 columns
    • customer_idinteger
    • first_namevarchar
    • last_namevarchar
    • emailvarchar
    • cityvarchar
    • statevarchar
    • signup_datedate
    • segmentvarchar
    • referral_sourcevarchar
    First 5 rows of customers
    customer_idfirst_namelast_nameemailcitystatesignup_datesegmentreferral_source
    1OwenHudsonowen.hudson@icloud.comSan FranciscoCA2022-06-02consumersearch
    2DouglasMendozadmendoza69@gmail.comAtlantaGA2022-06-02consumerNaN
    3HenryBrookshbrooks@lakesidecafe.comLos AngelesCA2022-06-04businessNaN
    4BrianGrahambgraham@bluecedarhomes.comSeattleWA2022-06-06businesspinterest
    5KyleJimenezkjimenez27@yahoo.comIndianapolisIN2022-06-07consumerNaN
    products120 rows · 8 columns
    • product_idinteger
    • namevarchar
    • categoryvarchar
    • subcategoryvarchar
    • unit_pricedecimal
    • unit_costdecimal
    • launched_ondate
    • is_activeboolean
    First 5 rows of products
    product_idnamecategorysubcategoryunit_priceunit_costlaunched_onis_active
    101Vale Velvet LoveseatFurnitureSofas1659.00NaN2023-09-11true
    102Alder Oak Coffee TableFurnitureTables919.00503.502024-05-16true
    103Orchard Rattan Dining ChairFurnitureChairs789.00429.872023-05-27true
    104Upland Oak BookcaseFurnitureStorage429.00214.702022-12-20true
    105Avery Leather Bed FrameFurnitureBeds449.00232.702021-08-31true
    order_items30,338 rows · 6 columns
    • order_item_idinteger
    • order_idinteger
    • product_idinteger
    • quantityinteger
    • unit_pricedecimal
    • discount_pctdecimal
    First 5 rows of order_items
    order_item_idorder_idproduct_idquantityunit_pricediscount_pct
    11001121931.990.00
    21001154311.990.00
    31002154411.990.00
    410021941149.000.00
    51002193219.990.00
    returns1,673 rows · 5 columns
    • return_idinteger
    • order_item_idinteger
    • returned_ondate
    • reasonvarchar
    • refund_amountdecimal
    First 5 rows of returns
    return_idorder_item_idreturned_onreasonrefund_amount
    1142023-01-10damaged83.69
    2422023-01-10wrong_item19.99
    31052023-01-14wrong_item10.99
    4242023-01-16changed_mind26.99
    51262023-01-16late20.99
    employees60 rows · 8 columns
    • employee_idinteger
    • first_namevarchar
    • last_namevarchar
    • departmentvarchar
    • titlevarchar
    • manager_idinteger
    • hire_datedate
    • salaryinteger
    First 5 rows of employees
    employee_idfirst_namelast_namedepartmenttitlemanager_idhire_datesalary
    1CatherineHaleExecutiveChief Executive OfficerNaN2016-03-01285000
    2RobertKimExecutiveChief Operating Officer12017-01-09235000
    3MeganCollinsSalesHead of Sales12018-04-16172000
    4ChloeGutierrezSalesAccount Executive32020-01-2172000
    5FrankBellSalesAccount Executive32023-05-2173000
    web_sessions40,000 rows · 7 columns
    • session_idinteger
    • customer_idinteger
    • started_attimestamp
    • devicevarchar
    • sourcevarchar
    • pages_viewedinteger
    • convertedboolean
    First 5 rows of web_sessions
    session_idcustomer_idstarted_atdevicesourcepages_viewedconverted
    1NaN2023-01-01 23:02:24mobilepaid1false
    2182023-01-01 15:07:49desktoppaid1false
    3NaN2023-01-01 16:55:46desktopdirect7false
    4NaN2023-01-01 12:43:28mobileorganic3false
    5NaN2023-01-01 13:06:21mobilesocial2false
    marketing_spend3,276 rows · 3 columns
    • spend_datedate
    • channelvarchar
    • amountdecimal
    First 5 rows of marketing_spend
    spend_datechannelamount
    2023-01-01paid492.99
    2023-01-01email37.38
    2023-01-01social200.53
    2023-01-02paid709.13
    2023-01-02email64.13

    The lesson

    Split, apply, combine

    groupby does three things in one call:

    1. Split the rows into groups that share a value (one group per channel).
    2. Apply a calculation to each group (the mean shipping fee).
    3. Combine the answers into a new Series or DataFrame, one row per group.
    orders.groupby("channel")["shipping_fee"].mean()
    channel
    app            ...
    marketplace    ...
    web            ...
    Name: shipping_fee, dtype: float64

    Read it left to right: group orders by channel, take the shipping_fee column, average it. The group keys become the index of the result, sorted A to Z by default.

    Common aggregations

    method per group
    .sum() total
    .mean() / .median() average / middle value
    .min() / .max() extremes
    .count() non-missing values in the column
    .size() rows, missing or not
    .nunique() distinct values

    count and size look alike but answer different questions:

    orders.groupby("channel")["coupon_code"].count()   # orders WITH a coupon, per channel
    orders.groupby("channel").size()                    # all orders, per channel

    count skips missing values, so it’s a count of coupons used. size counts rows. Mixing them up produces numbers that look plausible and are wrong, which is the worst kind.

    Series or DataFrame?

    Selecting one column after groupby gives a Series indexed by the group. To get an ordinary two-column table, which is usually what you want for display, merging or export, use reset_index() or as_index=False:

    orders.groupby("channel")["shipping_fee"].mean().reset_index()
    orders.groupby("channel", as_index=False)["shipping_fee"].mean()

    Both give a DataFrame with columns channel and shipping_fee.

    Reading the result

    The average fee per channel mixes free-shipping orders (fee 0) with paid ones. That’s a fair answer to “what does shipping bring in per order?”, but not to “what do people pay when they pay?”. For the second question, filter first:

    paid = orders[orders["shipping_fee"] > 0]
    paid.groupby("channel")["shipping_fee"].mean()

    Same code, different rows, different meaning. Always ask which population the question is about before you group.

    Sorting the output

    The result is sorted by the group key. To rank groups by the value instead, sort afterwards: .sort_values(ascending=False).

    Common mistakes

    • Forgetting to select a column: orders.groupby("channel").mean() tries to average every column and fails on text columns in pandas 2. Select what you need, or pass numeric_only=True.
    • Using count() when you mean “number of rows”.
    • Comparing averages without the group sizes. A channel with few orders can have an extreme mean by chance; show size() alongside.

    If you know SQL

    This is SELECT channel, AVG(shipping_fee) FROM orders GROUP BY channel.