The request

From Brian Mitchell, Finance Analyst
Your goal
Set result to a dict: "std" the standard deviation of completed["order_value"] (pandas default), "iqr" the 75th minus the 25th percentile, "upper_fence" the 75th percentile plus 1.5 × IQR (these three rounded to 2), and "outliers" the number of orders above the upper fence (an int).
- Use the
ordersDataFramenot done yet - Use the
order_itemsDataFramenot done yet - Store a dict in
resultnot done yet
Your code
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Reference solution
| order_id | customer_id | order_date | status | channel |
|---|---|---|---|---|
| 1001 | 125 | 2023-01-01 20:51:19 | completed | web |
| 1002 | 156 | 2023-01-02 07:58:46 | completed | web |
| 1003 | 22 | 2023-01-02 10:25:27 | completed | marketplace |
| 1004 | 48 | 2023-01-02 11:21:51 | completed | marketplace |
Mote checks your result
Press Run. Each row that matches the goal becomes a firefly in your lantern.
What Brian gets, and why
DataFrames
Loaded for you as pandas DataFrames, plus pd and np.
orders12,000 rows · 7 columns
order_idintegercustomer_idintegerorder_datetimestampstatusvarcharchannelvarcharshipping_feedecimalcoupon_codevarchar
| order_id | customer_id | order_date | status | channel | shipping_fee | coupon_code |
|---|---|---|---|---|---|---|
| 1001 | 125 | 2023-01-01 20:51:19 | completed | web | 0.00 | NaN |
| 1002 | 156 | 2023-01-02 07:58:46 | completed | web | 0.00 | NaN |
| 1003 | 22 | 2023-01-02 10:25:27 | completed | marketplace | 4.99 | WELCOME10 |
| 1004 | 48 | 2023-01-02 11:21:51 | completed | marketplace | 4.99 | WELCOME10 |
| 1005 | 82 | 2023-01-02 11:43:36 | completed | web | 0.00 | WELCOME10 |
order_items30,338 rows · 6 columns
order_item_idintegerorder_idintegerproduct_idintegerquantityintegerunit_pricedecimaldiscount_pctdecimal
| order_item_id | order_id | product_id | quantity | unit_price | discount_pct |
|---|---|---|---|---|---|
| 1 | 1001 | 121 | 9 | 31.99 | 0.00 |
| 2 | 1001 | 154 | 3 | 11.99 | 0.00 |
| 3 | 1002 | 154 | 4 | 11.99 | 0.00 |
| 4 | 1002 | 194 | 1 | 149.00 | 0.00 |
| 5 | 1002 | 193 | 2 | 19.99 | 0.00 |
customers2,018 rows · 9 columns
customer_idintegerfirst_namevarcharlast_namevarcharemailvarcharcityvarcharstatevarcharsignup_datedatesegmentvarcharreferral_sourcevarchar
| customer_id | first_name | last_name | city | state | signup_date | segment | referral_source | |
|---|---|---|---|---|---|---|---|---|
| 1 | Owen | Hudson | owen.hudson@icloud.com | San Francisco | CA | 2022-06-02 | consumer | search |
| 2 | Douglas | Mendoza | dmendoza69@gmail.com | Atlanta | GA | 2022-06-02 | consumer | NaN |
| 3 | Henry | Brooks | hbrooks@lakesidecafe.com | Los Angeles | CA | 2022-06-04 | business | NaN |
| 4 | Brian | Graham | bgraham@bluecedarhomes.com | Seattle | WA | 2022-06-06 | business | |
| 5 | Kyle | Jimenez | kjimenez27@yahoo.com | Indianapolis | IN | 2022-06-07 | consumer | NaN |
products120 rows · 8 columns
product_idintegernamevarcharcategoryvarcharsubcategoryvarcharunit_pricedecimalunit_costdecimallaunched_ondateis_activeboolean
| product_id | name | category | subcategory | unit_price | unit_cost | launched_on | is_active |
|---|---|---|---|---|---|---|---|
| 101 | Vale Velvet Loveseat | Furniture | Sofas | 1659.00 | NaN | 2023-09-11 | true |
| 102 | Alder Oak Coffee Table | Furniture | Tables | 919.00 | 503.50 | 2024-05-16 | true |
| 103 | Orchard Rattan Dining Chair | Furniture | Chairs | 789.00 | 429.87 | 2023-05-27 | true |
| 104 | Upland Oak Bookcase | Furniture | Storage | 429.00 | 214.70 | 2022-12-20 | true |
| 105 | Avery Leather Bed Frame | Furniture | Beds | 449.00 | 232.70 | 2021-08-31 | true |
returns1,673 rows · 5 columns
return_idintegerorder_item_idintegerreturned_ondatereasonvarcharrefund_amountdecimal
| return_id | order_item_id | returned_on | reason | refund_amount |
|---|---|---|---|---|
| 1 | 14 | 2023-01-10 | damaged | 83.69 |
| 2 | 42 | 2023-01-10 | wrong_item | 19.99 |
| 3 | 105 | 2023-01-14 | wrong_item | 10.99 |
| 4 | 24 | 2023-01-16 | changed_mind | 26.99 |
| 5 | 126 | 2023-01-16 | late | 20.99 |
employees60 rows · 8 columns
employee_idintegerfirst_namevarcharlast_namevarchardepartmentvarchartitlevarcharmanager_idintegerhire_datedatesalaryinteger
| employee_id | first_name | last_name | department | title | manager_id | hire_date | salary |
|---|---|---|---|---|---|---|---|
| 1 | Catherine | Hale | Executive | Chief Executive Officer | NaN | 2016-03-01 | 285000 |
| 2 | Robert | Kim | Executive | Chief Operating Officer | 1 | 2017-01-09 | 235000 |
| 3 | Megan | Collins | Sales | Head of Sales | 1 | 2018-04-16 | 172000 |
| 4 | Chloe | Gutierrez | Sales | Account Executive | 3 | 2020-01-21 | 72000 |
| 5 | Frank | Bell | Sales | Account Executive | 3 | 2023-05-21 | 73000 |
web_sessions40,000 rows · 7 columns
session_idintegercustomer_idintegerstarted_attimestampdevicevarcharsourcevarcharpages_viewedintegerconvertedboolean
| session_id | customer_id | started_at | device | source | pages_viewed | converted |
|---|---|---|---|---|---|---|
| 1 | NaN | 2023-01-01 23:02:24 | mobile | paid | 1 | false |
| 2 | 18 | 2023-01-01 15:07:49 | desktop | paid | 1 | false |
| 3 | NaN | 2023-01-01 16:55:46 | desktop | direct | 7 | false |
| 4 | NaN | 2023-01-01 12:43:28 | mobile | organic | 3 | false |
| 5 | NaN | 2023-01-01 13:06:21 | mobile | social | 2 | false |
marketing_spend3,276 rows · 3 columns
spend_datedatechannelvarcharamountdecimal
| spend_date | channel | amount |
|---|---|---|
| 2023-01-01 | paid | 492.99 |
| 2023-01-01 | 37.38 | |
| 2023-01-01 | social | 200.53 |
| 2023-01-02 | paid | 709.13 |
| 2023-01-02 | 64.13 |
The lesson
Why spread matters
Two stores can have the same median order and very different businesses: one where every order is close to $270, one where orders range from $10 to $10,000. The middle tells you where the data sits; the spread tells you how much to trust that any single order looks like it. Forecasts, sample sizes and A/B tests (chapter 3) all depend on it.
Standard deviation
The standard deviation is roughly “the typical distance from the mean”. pandas computes it by squaring each value’s distance from the mean, averaging the squares (dividing by n − 1), and taking the square root:
v = completed["order_value"]
v.std() # 795.75
pandas divides by n − 1 (the sample standard deviation) by default; NumPy’s np.std divides by n
unless you pass ddof=1. On 10,849 orders the difference is invisible, on 10 values it isn’t.
Squaring makes big distances count a lot. One $11,000 order is $10,500 from the mean, and its square outweighs hundreds of ordinary orders. That’s why the standard deviation of order value ($795.75) is bigger than the median order ($268.94).
Interquartile range
The IQR is the width of the middle half of the data: P75 minus P25.
q1, q3 = v.quantile(0.25), v.quantile(0.75) # 93.99, 659.87
iqr = q3 - q1 # 565.88
Like the median, it is robust: the biggest orders can grow without limit and the IQR does not move. For skewed data, report the median with the IQR (“median $269, middle half between $94 and $660”), and the mean with the standard deviation.
The 1.5 × IQR rule
A common way to flag unusual values is Tukey’s fences: anything above P75 + 1.5 × IQR or below P25 − 1.5 × IQR. These are the dots beyond the whiskers on a box plot.
fence = q3 + 1.5 * iqr # 1508.69
(v > fence).sum() # 927 orders
On order values the lower fence is negative, so nothing is flagged on that side. On the top, 927 orders are flagged; 70% of them come from business accounts, and furniture and outdoor sets make up most of their value. The rule found the tail of a skewed distribution, which is not the same as finding mistakes. Level 5 is about telling the two apart.
Common mistakes
- Rounding too early. Round the final numbers, not the quartiles you build the fence from.
- Reading “outlier” as “error”. The fence is a flag for a closer look. Deleting 8.5% of orders, including your largest customers, would make every revenue figure wrong.
- Using the standard deviation to describe skewed data. “Mean $543 ± $796” suggests negative orders are normal. Use the median and IQR there.
Lantern lit!
Practised: standard deviationiqrspreadoutliers
- Solved
- No hints
- First run
