1. Lighthouse

Level 7 · Group coupon codes into campaigns

The request

From Jordan Reyes, Head of Marketing

“Here's how our coupon codes roll up into campaigns. Count the coupon orders per campaign for me. If a code isn't on my list, don't guess, label it 'Unmapped' so I can see what I forgot.”

Your goal

Keep only orders that have a coupon_code. Map coupon_code to a campaign with campaigns (given) using Series.map; codes not in the dictionary become NaN, so fill those with 'Unmapped'. Set result to a DataFrame with columns campaign and n_orders (orders per campaign), sorted by n_orders descending, index reset.

  • Use the orders DataFramenot done yet
  • Show exactly campaign n_ordersnot done yet
  • 4 rows, sorted as askednot done yet

Your code

Python

Loading the editor…

    ResultPreview of orders · press Run to see yours
    Preview of orders
    order_idcustomer_idorder_datestatuschannel
    10011252023-01-01 20:51:19completedweb
    10021562023-01-02 07:58:46completedweb
    1003222023-01-02 10:25:27completedmarketplace
    1004482023-01-02 11:21:51completedmarketplace

    Mote checks your result

    Press Run. Each row that matches the goal becomes a firefly in your lantern.

    DataFrames

    Loaded for you as pandas DataFrames, plus pd and np.

    orders12,000 rows · 7 columns
    • order_idinteger
    • customer_idinteger
    • order_datetimestamp
    • statusvarchar
    • channelvarchar
    • shipping_feedecimal
    • coupon_codevarchar
    First 5 rows of orders
    order_idcustomer_idorder_datestatuschannelshipping_feecoupon_code
    10011252023-01-01 20:51:19completedweb0.00NaN
    10021562023-01-02 07:58:46completedweb0.00NaN
    1003222023-01-02 10:25:27completedmarketplace4.99WELCOME10
    1004482023-01-02 11:21:51completedmarketplace4.99WELCOME10
    1005822023-01-02 11:43:36completedweb0.00WELCOME10
    customers2,018 rows · 9 columns
    • customer_idinteger
    • first_namevarchar
    • last_namevarchar
    • emailvarchar
    • cityvarchar
    • statevarchar
    • signup_datedate
    • segmentvarchar
    • referral_sourcevarchar
    First 5 rows of customers
    customer_idfirst_namelast_nameemailcitystatesignup_datesegmentreferral_source
    1OwenHudsonowen.hudson@icloud.comSan FranciscoCA2022-06-02consumersearch
    2DouglasMendozadmendoza69@gmail.comAtlantaGA2022-06-02consumerNaN
    3HenryBrookshbrooks@lakesidecafe.comLos AngelesCA2022-06-04businessNaN
    4BrianGrahambgraham@bluecedarhomes.comSeattleWA2022-06-06businesspinterest
    5KyleJimenezkjimenez27@yahoo.comIndianapolisIN2022-06-07consumerNaN
    products120 rows · 8 columns
    • product_idinteger
    • namevarchar
    • categoryvarchar
    • subcategoryvarchar
    • unit_pricedecimal
    • unit_costdecimal
    • launched_ondate
    • is_activeboolean
    First 5 rows of products
    product_idnamecategorysubcategoryunit_priceunit_costlaunched_onis_active
    101Vale Velvet LoveseatFurnitureSofas1659.00NaN2023-09-11true
    102Alder Oak Coffee TableFurnitureTables919.00503.502024-05-16true
    103Orchard Rattan Dining ChairFurnitureChairs789.00429.872023-05-27true
    104Upland Oak BookcaseFurnitureStorage429.00214.702022-12-20true
    105Avery Leather Bed FrameFurnitureBeds449.00232.702021-08-31true
    order_items30,338 rows · 6 columns
    • order_item_idinteger
    • order_idinteger
    • product_idinteger
    • quantityinteger
    • unit_pricedecimal
    • discount_pctdecimal
    First 5 rows of order_items
    order_item_idorder_idproduct_idquantityunit_pricediscount_pct
    11001121931.990.00
    21001154311.990.00
    31002154411.990.00
    410021941149.000.00
    51002193219.990.00
    returns1,673 rows · 5 columns
    • return_idinteger
    • order_item_idinteger
    • returned_ondate
    • reasonvarchar
    • refund_amountdecimal
    First 5 rows of returns
    return_idorder_item_idreturned_onreasonrefund_amount
    1142023-01-10damaged83.69
    2422023-01-10wrong_item19.99
    31052023-01-14wrong_item10.99
    4242023-01-16changed_mind26.99
    51262023-01-16late20.99
    employees60 rows · 8 columns
    • employee_idinteger
    • first_namevarchar
    • last_namevarchar
    • departmentvarchar
    • titlevarchar
    • manager_idinteger
    • hire_datedate
    • salaryinteger
    First 5 rows of employees
    employee_idfirst_namelast_namedepartmenttitlemanager_idhire_datesalary
    1CatherineHaleExecutiveChief Executive OfficerNaN2016-03-01285000
    2RobertKimExecutiveChief Operating Officer12017-01-09235000
    3MeganCollinsSalesHead of Sales12018-04-16172000
    4ChloeGutierrezSalesAccount Executive32020-01-2172000
    5FrankBellSalesAccount Executive32023-05-2173000
    web_sessions40,000 rows · 7 columns
    • session_idinteger
    • customer_idinteger
    • started_attimestamp
    • devicevarchar
    • sourcevarchar
    • pages_viewedinteger
    • convertedboolean
    First 5 rows of web_sessions
    session_idcustomer_idstarted_atdevicesourcepages_viewedconverted
    1NaN2023-01-01 23:02:24mobilepaid1false
    2182023-01-01 15:07:49desktoppaid1false
    3NaN2023-01-01 16:55:46desktopdirect7false
    4NaN2023-01-01 12:43:28mobileorganic3false
    5NaN2023-01-01 13:06:21mobilesocial2false
    marketing_spend3,276 rows · 3 columns
    • spend_datedate
    • channelvarchar
    • amountdecimal
    First 5 rows of marketing_spend
    spend_datechannelamount
    2023-01-01paid492.99
    2023-01-01email37.38
    2023-01-01social200.53
    2023-01-02paid709.13
    2023-01-02email64.13

    The lesson

    map: look every value up in a dictionary

    Series.map(d) replaces each value with d[value]. It’s the pandas version of looking a code up in a reference table:

    campaigns = {"WELCOME10": "Onboarding", "SPRING15": "Seasonal", "SUMMER15": "Seasonal",
                 "BFCM25": "Holiday", "HOLIDAY20": "Holiday"}
    orders["coupon_code"].map(campaigns).head()

    The important detail is what happens to a value that isn’t a key. A plain Python dictionary raises KeyError for a missing key; map doesn’t. It quietly returns NaN. Orders with no coupon (NaN in coupon_code) also come back as NaN, since NaN isn’t a key either.

    Make the gaps visible

    Harbor & Pine has six coupon codes, but Jordan’s list has five. FREESHIP is missing, so its orders map to NaN:

    coupon_orders = orders[orders["coupon_code"].notna()].copy()
    mapped = coupon_orders["coupon_code"].map(campaigns)
    mapped.isna().sum()      # 193, all FREESHIP

    If you group now, those 193 orders disappear, because groupby leaves NaN keys out by default. The totals would add up to 1,530 instead of the 1,723 orders that used a coupon, and nobody would be told why. fillna("Unmapped") turns the silent gap into a row Jordan can see and act on.

    This is why we filter to coupon orders first. Otherwise the 10,277 orders without any coupon would also become NaN and then “Unmapped”, mixing “no coupon” with “a code I forgot”.

    The result

    campaign n_orders
    Onboarding 587
    Holiday 541
    Seasonal 402
    Unmapped 193

    WELCOME10 alone is the single most used code. Holiday combines BFCM25 (348 orders) and HOLIDAY20 (193). When Jordan adds FREESHIP to the dictionary, the Unmapped row will disappear, which is exactly how a lookup table should behave. A quick reconciliation proves nothing was lost: 587 + 541 + 402 + 193 = 1,723, the number of orders with any coupon.

    Common mistakes

    • Grouping straight after map, so unmapped codes vanish from the totals.
    • Using .replace(campaigns) instead: it leaves unknown codes unchanged, so FREESHIP would look like a campaign name.
    • Mapping the whole orders table, so “no coupon” and “unknown coupon” end up in the same bucket.
    • Expecting map to raise an error for a missing key, the way a plain dictionary lookup does.

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