1. Lighthouse

Level 8 · Social-media shoppers on iPhone email

The request

From Jordan Reyes, Head of Marketing

“We're testing an Apple Mail promo for shoppers who found us on social. I need every consumer customer referred by Instagram, TikTok or Pinterest whose email ends in @icloud.com, oldest signup first.”

Your goal

Set result to a DataFrame of customers whose segment is 'consumer', whose referral_source is 'instagram', 'tiktok' or 'pinterest', and whose email ends with '@icloud.com'. Columns customer_id, email, referral_source, signup_date (in that order), sorted by signup_date ascending then customer_id ascending, index reset.

  • Use the customers DataFramenot done yet
  • Show exactly customer_id email referral_source signup_datenot done yet
  • 50 rows, sorted as askednot done yet

Your code

Python

Loading the editor…

    ResultPreview of customers · press Run to see yours
    Preview of customers
    customer_idfirst_namelast_nameemailcity
    1OwenHudsonowen.hudson@icloud.comSan Francisco
    2DouglasMendozadmendoza69@gmail.comAtlanta
    3HenryBrookshbrooks@lakesidecafe.comLos Angeles
    4BrianGrahambgraham@bluecedarhomes.comSeattle

    Mote checks your result

    Press Run. Each row that matches the goal becomes a firefly in your lantern.

    DataFrames

    Loaded for you as pandas DataFrames, plus pd and np.

    customers2,018 rows · 9 columns
    • customer_idinteger
    • first_namevarchar
    • last_namevarchar
    • emailvarchar
    • cityvarchar
    • statevarchar
    • signup_datedate
    • segmentvarchar
    • referral_sourcevarchar
    First 5 rows of customers
    customer_idfirst_namelast_nameemailcitystatesignup_datesegmentreferral_source
    1OwenHudsonowen.hudson@icloud.comSan FranciscoCA2022-06-02consumersearch
    2DouglasMendozadmendoza69@gmail.comAtlantaGA2022-06-02consumerNaN
    3HenryBrookshbrooks@lakesidecafe.comLos AngelesCA2022-06-04businessNaN
    4BrianGrahambgraham@bluecedarhomes.comSeattleWA2022-06-06businesspinterest
    5KyleJimenezkjimenez27@yahoo.comIndianapolisIN2022-06-07consumerNaN
    products120 rows · 8 columns
    • product_idinteger
    • namevarchar
    • categoryvarchar
    • subcategoryvarchar
    • unit_pricedecimal
    • unit_costdecimal
    • launched_ondate
    • is_activeboolean
    First 5 rows of products
    product_idnamecategorysubcategoryunit_priceunit_costlaunched_onis_active
    101Vale Velvet LoveseatFurnitureSofas1659.00NaN2023-09-11true
    102Alder Oak Coffee TableFurnitureTables919.00503.502024-05-16true
    103Orchard Rattan Dining ChairFurnitureChairs789.00429.872023-05-27true
    104Upland Oak BookcaseFurnitureStorage429.00214.702022-12-20true
    105Avery Leather Bed FrameFurnitureBeds449.00232.702021-08-31true
    orders12,000 rows · 7 columns
    • order_idinteger
    • customer_idinteger
    • order_datetimestamp
    • statusvarchar
    • channelvarchar
    • shipping_feedecimal
    • coupon_codevarchar
    First 5 rows of orders
    order_idcustomer_idorder_datestatuschannelshipping_feecoupon_code
    10011252023-01-01 20:51:19completedweb0.00NaN
    10021562023-01-02 07:58:46completedweb0.00NaN
    1003222023-01-02 10:25:27completedmarketplace4.99WELCOME10
    1004482023-01-02 11:21:51completedmarketplace4.99WELCOME10
    1005822023-01-02 11:43:36completedweb0.00WELCOME10
    order_items30,338 rows · 6 columns
    • order_item_idinteger
    • order_idinteger
    • product_idinteger
    • quantityinteger
    • unit_pricedecimal
    • discount_pctdecimal
    First 5 rows of order_items
    order_item_idorder_idproduct_idquantityunit_pricediscount_pct
    11001121931.990.00
    21001154311.990.00
    31002154411.990.00
    410021941149.000.00
    51002193219.990.00
    returns1,673 rows · 5 columns
    • return_idinteger
    • order_item_idinteger
    • returned_ondate
    • reasonvarchar
    • refund_amountdecimal
    First 5 rows of returns
    return_idorder_item_idreturned_onreasonrefund_amount
    1142023-01-10damaged83.69
    2422023-01-10wrong_item19.99
    31052023-01-14wrong_item10.99
    4242023-01-16changed_mind26.99
    51262023-01-16late20.99
    employees60 rows · 8 columns
    • employee_idinteger
    • first_namevarchar
    • last_namevarchar
    • departmentvarchar
    • titlevarchar
    • manager_idinteger
    • hire_datedate
    • salaryinteger
    First 5 rows of employees
    employee_idfirst_namelast_namedepartmenttitlemanager_idhire_datesalary
    1CatherineHaleExecutiveChief Executive OfficerNaN2016-03-01285000
    2RobertKimExecutiveChief Operating Officer12017-01-09235000
    3MeganCollinsSalesHead of Sales12018-04-16172000
    4ChloeGutierrezSalesAccount Executive32020-01-2172000
    5FrankBellSalesAccount Executive32023-05-2173000
    web_sessions40,000 rows · 7 columns
    • session_idinteger
    • customer_idinteger
    • started_attimestamp
    • devicevarchar
    • sourcevarchar
    • pages_viewedinteger
    • convertedboolean
    First 5 rows of web_sessions
    session_idcustomer_idstarted_atdevicesourcepages_viewedconverted
    1NaN2023-01-01 23:02:24mobilepaid1false
    2182023-01-01 15:07:49desktoppaid1false
    3NaN2023-01-01 16:55:46desktopdirect7false
    4NaN2023-01-01 12:43:28mobileorganic3false
    5NaN2023-01-01 13:06:21mobilesocial2false
    marketing_spend3,276 rows · 3 columns
    • spend_datedate
    • channelvarchar
    • amountdecimal
    First 5 rows of marketing_spend
    spend_datechannelamount
    2023-01-01paid492.99
    2023-01-01email37.38
    2023-01-01social200.53
    2023-01-02paid709.13
    2023-01-02email64.13

    The lesson

    One mask per rule

    Jordan’s ticket has three rules, and each one becomes a mask. Naming them keeps the final filter short and makes it obvious which rule does what:

    is_consumer = customers["segment"] == "consumer"
    from_social = customers["referral_source"].isin(["instagram", "tiktok", "pinterest"])
    on_icloud = customers["email"].str.endswith("@icloud.com")
    
    audience = customers[is_consumer & from_social & on_icloud]

    isin is the clean way to say “is one of these values”. The alternative is three equality tests joined with |, inside their own parentheses, which is longer and easy to group wrongly.

    str.endswith checks how a piece of text ends. It’s the right tool for an email domain: "@icloud.com" must be the very end of the address. str.contains("icloud") would also match a Gmail address that happens to include “icloud” in the name part.

    What about missing values?

    referral_source is missing (NaN) for 666 customers. isin simply returns False for them, so they drop out, which is what we want: an unknown source isn’t a social referral. str.endswith would return NaN for a missing email, but every customer has one, so the mask is clean here. On a column with gaps you’d add na=False, just as with str.contains.

    Sorting with a tie-breaker

    Several customers can sign up on the same day, so sorting by signup_date alone could list them in any order. Adding customer_id as a second sort key makes the order fully predictable:

    audience.sort_values(["signup_date", "customer_id"])

    The list has 50 customers. The oldest signup is customer 67 (2022-08-26, via TikTok), and the newest is customer 1999, who signed up on 2025-12-31. Instagram brings in half of them (25), TikTok 15 and Pinterest 10, which matches Instagram being the biggest social source in the whole table (218 customers).

    Common mistakes

    • Writing customers["referral_source"] == "instagram" | "tiktok", which fails. Use isin.
    • Using str.contains("icloud") when the rule is about how the address ends.
    • Joining masks with and instead of &.
    • Sorting only by signup_date, so customers who signed up on the same day can come out in a different order than the one asked for.

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