The request

From Laura Bennett, Head of Finance
Your goal
Using order lines with quantity > 0 from orders with status 'completed' placed in 2025, compute each order's value (sum of quantity * unit_price * (1 - discount_pct / 100)). Set result to a dict with keys q1, q3 (the 25th and 75th percentiles of order value), upper_fence (q3 + 1.5 * (q3 - q1)), all rounded to 2, and n_outliers (the number of orders with a value above upper_fence, an int).
- Use the
ordersDataFramenot done yet - Use the
order_itemsDataFramenot done yet - Store a dict in
resultnot done yet
Your code
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Reference solution
| order_id | customer_id | order_date | status | channel |
|---|---|---|---|---|
| 1001 | 125 | 2023-01-01 20:51:19 | completed | web |
| 1002 | 156 | 2023-01-02 07:58:46 | completed | web |
| 1003 | 22 | 2023-01-02 10:25:27 | completed | marketplace |
| 1004 | 48 | 2023-01-02 11:21:51 | completed | marketplace |
Mote checks your result
Press Run. Each row that matches the goal becomes a firefly in your lantern.
What Laura gets, and why
DataFrames
Loaded for you as pandas DataFrames, plus pd and np.
orders12,000 rows · 7 columns
order_idintegercustomer_idintegerorder_datetimestampstatusvarcharchannelvarcharshipping_feedecimalcoupon_codevarchar
| order_id | customer_id | order_date | status | channel | shipping_fee | coupon_code |
|---|---|---|---|---|---|---|
| 1001 | 125 | 2023-01-01 20:51:19 | completed | web | 0.00 | NaN |
| 1002 | 156 | 2023-01-02 07:58:46 | completed | web | 0.00 | NaN |
| 1003 | 22 | 2023-01-02 10:25:27 | completed | marketplace | 4.99 | WELCOME10 |
| 1004 | 48 | 2023-01-02 11:21:51 | completed | marketplace | 4.99 | WELCOME10 |
| 1005 | 82 | 2023-01-02 11:43:36 | completed | web | 0.00 | WELCOME10 |
order_items30,338 rows · 6 columns
order_item_idintegerorder_idintegerproduct_idintegerquantityintegerunit_pricedecimaldiscount_pctdecimal
| order_item_id | order_id | product_id | quantity | unit_price | discount_pct |
|---|---|---|---|---|---|
| 1 | 1001 | 121 | 9 | 31.99 | 0.00 |
| 2 | 1001 | 154 | 3 | 11.99 | 0.00 |
| 3 | 1002 | 154 | 4 | 11.99 | 0.00 |
| 4 | 1002 | 194 | 1 | 149.00 | 0.00 |
| 5 | 1002 | 193 | 2 | 19.99 | 0.00 |
customers2,018 rows · 9 columns
customer_idintegerfirst_namevarcharlast_namevarcharemailvarcharcityvarcharstatevarcharsignup_datedatesegmentvarcharreferral_sourcevarchar
| customer_id | first_name | last_name | city | state | signup_date | segment | referral_source | |
|---|---|---|---|---|---|---|---|---|
| 1 | Owen | Hudson | owen.hudson@icloud.com | San Francisco | CA | 2022-06-02 | consumer | search |
| 2 | Douglas | Mendoza | dmendoza69@gmail.com | Atlanta | GA | 2022-06-02 | consumer | NaN |
| 3 | Henry | Brooks | hbrooks@lakesidecafe.com | Los Angeles | CA | 2022-06-04 | business | NaN |
| 4 | Brian | Graham | bgraham@bluecedarhomes.com | Seattle | WA | 2022-06-06 | business | |
| 5 | Kyle | Jimenez | kjimenez27@yahoo.com | Indianapolis | IN | 2022-06-07 | consumer | NaN |
products120 rows · 8 columns
product_idintegernamevarcharcategoryvarcharsubcategoryvarcharunit_pricedecimalunit_costdecimallaunched_ondateis_activeboolean
| product_id | name | category | subcategory | unit_price | unit_cost | launched_on | is_active |
|---|---|---|---|---|---|---|---|
| 101 | Vale Velvet Loveseat | Furniture | Sofas | 1659.00 | NaN | 2023-09-11 | true |
| 102 | Alder Oak Coffee Table | Furniture | Tables | 919.00 | 503.50 | 2024-05-16 | true |
| 103 | Orchard Rattan Dining Chair | Furniture | Chairs | 789.00 | 429.87 | 2023-05-27 | true |
| 104 | Upland Oak Bookcase | Furniture | Storage | 429.00 | 214.70 | 2022-12-20 | true |
| 105 | Avery Leather Bed Frame | Furniture | Beds | 449.00 | 232.70 | 2021-08-31 | true |
returns1,673 rows · 5 columns
return_idintegerorder_item_idintegerreturned_ondatereasonvarcharrefund_amountdecimal
| return_id | order_item_id | returned_on | reason | refund_amount |
|---|---|---|---|---|
| 1 | 14 | 2023-01-10 | damaged | 83.69 |
| 2 | 42 | 2023-01-10 | wrong_item | 19.99 |
| 3 | 105 | 2023-01-14 | wrong_item | 10.99 |
| 4 | 24 | 2023-01-16 | changed_mind | 26.99 |
| 5 | 126 | 2023-01-16 | late | 20.99 |
employees60 rows · 8 columns
employee_idintegerfirst_namevarcharlast_namevarchardepartmentvarchartitlevarcharmanager_idintegerhire_datedatesalaryinteger
| employee_id | first_name | last_name | department | title | manager_id | hire_date | salary |
|---|---|---|---|---|---|---|---|
| 1 | Catherine | Hale | Executive | Chief Executive Officer | NaN | 2016-03-01 | 285000 |
| 2 | Robert | Kim | Executive | Chief Operating Officer | 1 | 2017-01-09 | 235000 |
| 3 | Megan | Collins | Sales | Head of Sales | 1 | 2018-04-16 | 172000 |
| 4 | Chloe | Gutierrez | Sales | Account Executive | 3 | 2020-01-21 | 72000 |
| 5 | Frank | Bell | Sales | Account Executive | 3 | 2023-05-21 | 73000 |
web_sessions40,000 rows · 7 columns
session_idintegercustomer_idintegerstarted_attimestampdevicevarcharsourcevarcharpages_viewedintegerconvertedboolean
| session_id | customer_id | started_at | device | source | pages_viewed | converted |
|---|---|---|---|---|---|---|
| 1 | NaN | 2023-01-01 23:02:24 | mobile | paid | 1 | false |
| 2 | 18 | 2023-01-01 15:07:49 | desktop | paid | 1 | false |
| 3 | NaN | 2023-01-01 16:55:46 | desktop | direct | 7 | false |
| 4 | NaN | 2023-01-01 12:43:28 | mobile | organic | 3 | false |
| 5 | NaN | 2023-01-01 13:06:21 | mobile | social | 2 | false |
marketing_spend3,276 rows · 3 columns
spend_datedatechannelvarcharamountdecimal
| spend_date | channel | amount |
|---|---|---|
| 2023-01-01 | paid | 492.99 |
| 2023-01-01 | 37.38 | |
| 2023-01-01 | social | 200.53 |
| 2023-01-02 | paid | 709.13 |
| 2023-01-02 | 64.13 |
The lesson
A rule instead of a feeling
“Unusually large” needs a definition you can write down and repeat. The usual one is the 1.5 × IQR rule, the same rule a boxplot uses for its whiskers:
- compute Q1 and Q3, the 25th and 75th percentiles;
- the IQR is Q3 - Q1, the spread of the middle half;
- the upper fence is Q3 + 1.5 × IQR, the lower fence Q1 - 1.5 × IQR;
- values beyond a fence are outliers.
It works on skewed data like order values because quartiles, unlike the mean and the standard deviation, aren’t dragged around by the extremes they’re trying to detect.
In pandas
quantile accepts a list and returns one value per fraction, which unpacks neatly:
q1, q3 = order_value.quantile([0.25, 0.75]) # 87.94, 650.48
iqr = q3 - q1 # 562.53
upper = q3 + 1.5 * iqr # 1494.27
lower = q1 - 1.5 * iqr # negative: no low outliers possible
outliers = order_value[order_value > upper]
len(outliers) # 370
Out of 4,295 completed 2025 orders, 370 are above $1,494.27, about 8.6%. That’s more than you’d see in a symmetric distribution, which is the long right tail again.
A seaborn boxplot of a single Series shows the same thing: sns.boxplot(x=order_value). Every dot
to the right of the whisker is one of those 370 orders, and an axvline at the fence makes the rule
visible.
Outlier is not the same as wrong
The next step is to look at who the outliers are, never to delete them on sight. Joining the segment shows that 256 of the 370 come from business accounts, which make up about a quarter of all orders. They’re unusual, and they’re some of the most valuable orders the store has. Dropping them would cut a large slice of revenue out of every total.
What you do depends on the question. For “what does a typical order look like”, report the median, which isn’t moved by them anyway. For revenue, keep them. For a model that would be thrown off by them, cap or segment them, and write down that decision and why. An outlier that is a real error, like a negative quantity, is a cleaning problem with its own rule.
Common mistakes
- Using
quantile(25): quantile takes fractions, 0.25 and 0.75. - Computing the fences on order lines instead of orders.
- Dropping outliers without checking what they are.
- Forgetting the lower fence exists. Here it’s negative, so it flags nothing, but say so.
Lantern lit!
Practised: outliersiqrquantileboxplotfences
- Solved
- No hints
- First run
