1. Lighthouse

Level 8 · Debug: one order per customer on every channel?

The request

From Megan Collins, Head of Sales

“Brian sent me orders and customers per channel, but every channel shows exactly 1.00 orders per customer, and customers equals orders everywhere. We know people buy again, so the numbers look off. Can you fix it?”

Your goal

Fix the query. For orders with status 'completed', return one row per channel with: channel, orders (number of orders), customers (number of different customers who placed them) and orders_per_customer (orders divided by customers, rounded to 2).

  • Read from the customers tablenot done yet
  • Read from the orders tablenot done yet
  • Show exactly channel orders customers orders_per_customernot done yet

Your query

SQL

Loading the editor…

    ResultPreview of customers · press Run to see yours
    Preview of customers
    customer_idfirst_namelast_nameemailcity
    1OwenHudsonowen.hudson@icloud.comSan Francisco
    2DouglasMendozadmendoza69@gmail.comAtlanta
    3HenryBrookshbrooks@lakesidecafe.comLos Angeles
    4BrianGrahambgraham@bluecedarhomes.comSeattle

    Mote checks your result

    Press Run. Each row that matches the goal becomes a firefly in your lantern.

    Tables

    Harbor & Pine store data, ready to query.

    customers2,018 rows · 9 columns
    • customer_idinteger
    • first_namevarchar
    • last_namevarchar
    • emailvarchar
    • cityvarchar
    • statevarchar
    • signup_datedate
    • segmentvarchar
    • referral_sourcevarchar
    First 5 rows of customers
    customer_idfirst_namelast_nameemailcitystatesignup_datesegmentreferral_source
    1OwenHudsonowen.hudson@icloud.comSan FranciscoCA2022-06-02consumersearch
    2DouglasMendozadmendoza69@gmail.comAtlantaGA2022-06-02consumerNULL
    3HenryBrookshbrooks@lakesidecafe.comLos AngelesCA2022-06-04businessNULL
    4BrianGrahambgraham@bluecedarhomes.comSeattleWA2022-06-06businesspinterest
    5KyleJimenezkjimenez27@yahoo.comIndianapolisIN2022-06-07consumerNULL
    orders12,000 rows · 7 columns
    • order_idinteger
    • customer_idinteger
    • order_datetimestamp
    • statusvarchar
    • channelvarchar
    • shipping_feedecimal
    • coupon_codevarchar
    First 5 rows of orders
    order_idcustomer_idorder_datestatuschannelshipping_feecoupon_code
    10011252023-01-01 20:51:19completedweb0.00NULL
    10021562023-01-02 07:58:46completedweb0.00NULL
    1003222023-01-02 10:25:27completedmarketplace4.99WELCOME10
    1004482023-01-02 11:21:51completedmarketplace4.99WELCOME10
    1005822023-01-02 11:43:36completedweb0.00WELCOME10
    products120 rows · 8 columns
    • product_idinteger
    • namevarchar
    • categoryvarchar
    • subcategoryvarchar
    • unit_pricedecimal
    • unit_costdecimal
    • launched_ondate
    • is_activeboolean
    First 5 rows of products
    product_idnamecategorysubcategoryunit_priceunit_costlaunched_onis_active
    101Vale Velvet LoveseatFurnitureSofas1659.00NULL2023-09-11true
    102Alder Oak Coffee TableFurnitureTables919.00503.502024-05-16true
    103Orchard Rattan Dining ChairFurnitureChairs789.00429.872023-05-27true
    104Upland Oak BookcaseFurnitureStorage429.00214.702022-12-20true
    105Avery Leather Bed FrameFurnitureBeds449.00232.702021-08-31true
    order_items30,338 rows · 6 columns
    • order_item_idinteger
    • order_idinteger
    • product_idinteger
    • quantityinteger
    • unit_pricedecimal
    • discount_pctdecimal
    First 5 rows of order_items
    order_item_idorder_idproduct_idquantityunit_pricediscount_pct
    11001121931.990.00
    21001154311.990.00
    31002154411.990.00
    410021941149.000.00
    51002193219.990.00
    returns1,673 rows · 5 columns
    • return_idinteger
    • order_item_idinteger
    • returned_ondate
    • reasonvarchar
    • refund_amountdecimal
    First 5 rows of returns
    return_idorder_item_idreturned_onreasonrefund_amount
    1142023-01-10damaged83.69
    2422023-01-10wrong_item19.99
    31052023-01-14wrong_item10.99
    4242023-01-16changed_mind26.99
    51262023-01-16late20.99
    employees60 rows · 8 columns
    • employee_idinteger
    • first_namevarchar
    • last_namevarchar
    • departmentvarchar
    • titlevarchar
    • manager_idinteger
    • hire_datedate
    • salaryinteger
    First 5 rows of employees
    employee_idfirst_namelast_namedepartmenttitlemanager_idhire_datesalary
    1CatherineHaleExecutiveChief Executive OfficerNULL2016-03-01285000
    2RobertKimExecutiveChief Operating Officer12017-01-09235000
    3MeganCollinsSalesHead of Sales12018-04-16172000
    4ChloeGutierrezSalesAccount Executive32020-01-2172000
    5FrankBellSalesAccount Executive32023-05-2173000
    web_sessions40,000 rows · 7 columns
    • session_idinteger
    • customer_idinteger
    • started_attimestamp
    • devicevarchar
    • sourcevarchar
    • pages_viewedinteger
    • convertedboolean
    First 5 rows of web_sessions
    session_idcustomer_idstarted_atdevicesourcepages_viewedconverted
    1NULL2023-01-01 23:02:24mobilepaid1false
    2182023-01-01 15:07:49desktoppaid1false
    3NULL2023-01-01 16:55:46desktopdirect7false
    4NULL2023-01-01 12:43:28mobileorganic3false
    5NULL2023-01-01 13:06:21mobilesocial2false
    marketing_spend3,276 rows · 3 columns
    • spend_datedate
    • channelvarchar
    • amountdecimal
    First 5 rows of marketing_spend
    spend_datechannelamount
    2023-01-01paid492.99
    2023-01-01email37.38
    2023-01-01social200.53
    2023-01-02paid709.13
    2023-01-02email64.13

    The lesson

    A ratio that comes out at exactly 1.00 on every row is a strong sign that the top and bottom of the fraction are the same number. That is the case here.

    COUNT(column) is not COUNT(DISTINCT column)

    COUNT(customer_id) counts the rows where customer_id is not NULL. In orders it is never NULL, so on every channel it counts orders, exactly like COUNT(*). The question is how many different customers there are, and that needs DISTINCT:

    SELECT
      channel,
      COUNT(*) AS orders,
      COUNT(DISTINCT customer_id) AS customers
    FROM orders
    WHERE status = 'completed'
    GROUP BY channel;

    Web: 5,367 orders from 1,379 customers. App: 3,885 orders from 1,316 customers. Marketplace: 1,597 orders from 784 customers. Dividing gives 3.89, 2.95 and 2.04 orders per customer. The * 1.0 keeps the division decimal in every database.

    How to spot it

    • Two columns that should differ are identical on every row.
    • A ratio is a suspiciously round constant, like 1.00 or 100%.
    • The result contradicts something you know about the business, here that most customers order more than once.
    • A “customers” number is larger than you would expect the customer base to be. On web it was 5,367, while the whole store has about two thousand customers.

    Common mistakes

    • Summing the per-channel customer counts to get a total. A customer who used both web and app is counted on both rows, so the three counts add up to 3,479 even though only 1,730 different customers have a completed order. Count distinct customers without the GROUP BY for the true total.
    • Writing DISTINCT COUNT(customer_id). That applies DISTINCT to the finished count, not to the customer ids, and changes nothing.
    • Fixing the customers column but not the ratio. The ratio repeats the count, so it needs the same COUNT(DISTINCT customer_id) in its denominator, or it stays at 1.00 while the column next to it looks right.

    In SQL Server

    COUNT(DISTINCT ...) works the same. The * 1.0 matters more there: COUNT(*) / COUNT(DISTINCT customer_id) divides two integers and SQL Server truncates the result, so 3.89 would show as 3.

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