1. Lighthouse

Level 2 · Customers who never ordered

The request

From Lauren Hayes, Email Marketing Manager

“I want to run a first-purchase campaign. Can you find every customer who signed up but has never placed a single order, of any status?”

Your goal

Return customer_id, email and signup_date for every customer who has no row at all in orders.

  • Read from the customers tablenot done yet
  • Read from the orders tablenot done yet
  • Show exactly customer_id email signup_datenot done yet

Your query

SQL

Loading the editor…

    ResultPreview of customers · press Run to see yours
    Preview of customers
    customer_idfirst_namelast_nameemailcity
    1OwenHudsonowen.hudson@icloud.comSan Francisco
    2DouglasMendozadmendoza69@gmail.comAtlanta
    3HenryBrookshbrooks@lakesidecafe.comLos Angeles
    4BrianGrahambgraham@bluecedarhomes.comSeattle

    Mote checks your result

    Press Run. Each row that matches the goal becomes a firefly in your lantern.

    Tables

    Harbor & Pine store data, ready to query.

    customers2,018 rows · 9 columns
    • customer_idinteger
    • first_namevarchar
    • last_namevarchar
    • emailvarchar
    • cityvarchar
    • statevarchar
    • signup_datedate
    • segmentvarchar
    • referral_sourcevarchar
    First 5 rows of customers
    customer_idfirst_namelast_nameemailcitystatesignup_datesegmentreferral_source
    1OwenHudsonowen.hudson@icloud.comSan FranciscoCA2022-06-02consumersearch
    2DouglasMendozadmendoza69@gmail.comAtlantaGA2022-06-02consumerNULL
    3HenryBrookshbrooks@lakesidecafe.comLos AngelesCA2022-06-04businessNULL
    4BrianGrahambgraham@bluecedarhomes.comSeattleWA2022-06-06businesspinterest
    5KyleJimenezkjimenez27@yahoo.comIndianapolisIN2022-06-07consumerNULL
    orders12,000 rows · 7 columns
    • order_idinteger
    • customer_idinteger
    • order_datetimestamp
    • statusvarchar
    • channelvarchar
    • shipping_feedecimal
    • coupon_codevarchar
    First 5 rows of orders
    order_idcustomer_idorder_datestatuschannelshipping_feecoupon_code
    10011252023-01-01 20:51:19completedweb0.00NULL
    10021562023-01-02 07:58:46completedweb0.00NULL
    1003222023-01-02 10:25:27completedmarketplace4.99WELCOME10
    1004482023-01-02 11:21:51completedmarketplace4.99WELCOME10
    1005822023-01-02 11:43:36completedweb0.00WELCOME10
    products120 rows · 8 columns
    • product_idinteger
    • namevarchar
    • categoryvarchar
    • subcategoryvarchar
    • unit_pricedecimal
    • unit_costdecimal
    • launched_ondate
    • is_activeboolean
    First 5 rows of products
    product_idnamecategorysubcategoryunit_priceunit_costlaunched_onis_active
    101Vale Velvet LoveseatFurnitureSofas1659.00NULL2023-09-11true
    102Alder Oak Coffee TableFurnitureTables919.00503.502024-05-16true
    103Orchard Rattan Dining ChairFurnitureChairs789.00429.872023-05-27true
    104Upland Oak BookcaseFurnitureStorage429.00214.702022-12-20true
    105Avery Leather Bed FrameFurnitureBeds449.00232.702021-08-31true
    order_items30,338 rows · 6 columns
    • order_item_idinteger
    • order_idinteger
    • product_idinteger
    • quantityinteger
    • unit_pricedecimal
    • discount_pctdecimal
    First 5 rows of order_items
    order_item_idorder_idproduct_idquantityunit_pricediscount_pct
    11001121931.990.00
    21001154311.990.00
    31002154411.990.00
    410021941149.000.00
    51002193219.990.00
    returns1,673 rows · 5 columns
    • return_idinteger
    • order_item_idinteger
    • returned_ondate
    • reasonvarchar
    • refund_amountdecimal
    First 5 rows of returns
    return_idorder_item_idreturned_onreasonrefund_amount
    1142023-01-10damaged83.69
    2422023-01-10wrong_item19.99
    31052023-01-14wrong_item10.99
    4242023-01-16changed_mind26.99
    51262023-01-16late20.99
    employees60 rows · 8 columns
    • employee_idinteger
    • first_namevarchar
    • last_namevarchar
    • departmentvarchar
    • titlevarchar
    • manager_idinteger
    • hire_datedate
    • salaryinteger
    First 5 rows of employees
    employee_idfirst_namelast_namedepartmenttitlemanager_idhire_datesalary
    1CatherineHaleExecutiveChief Executive OfficerNULL2016-03-01285000
    2RobertKimExecutiveChief Operating Officer12017-01-09235000
    3MeganCollinsSalesHead of Sales12018-04-16172000
    4ChloeGutierrezSalesAccount Executive32020-01-2172000
    5FrankBellSalesAccount Executive32023-05-2173000
    web_sessions40,000 rows · 7 columns
    • session_idinteger
    • customer_idinteger
    • started_attimestamp
    • devicevarchar
    • sourcevarchar
    • pages_viewedinteger
    • convertedboolean
    First 5 rows of web_sessions
    session_idcustomer_idstarted_atdevicesourcepages_viewedconverted
    1NULL2023-01-01 23:02:24mobilepaid1false
    2182023-01-01 15:07:49desktoppaid1false
    3NULL2023-01-01 16:55:46desktopdirect7false
    4NULL2023-01-01 12:43:28mobileorganic3false
    5NULL2023-01-01 13:06:21mobilesocial2false
    marketing_spend3,276 rows · 3 columns
    • spend_datedate
    • channelvarchar
    • amountdecimal
    First 5 rows of marketing_spend
    spend_datechannelamount
    2023-01-01paid492.99
    2023-01-01email37.38
    2023-01-01social200.53
    2023-01-02paid709.13
    2023-01-02email64.13

    The lesson

    LEFT JOIN keeps every row from the left table, whether or not it finds a match. When there is no match, the columns from the right table are filled with NULL:

    SELECT c.customer_id, c.email, o.order_id
    FROM customers AS c
    LEFT JOIN orders AS o ON o.customer_id = c.customer_id;

    A customer with five orders appears five times. A customer with no orders appears once, with order_id NULL. Compare with JOIN, which would drop that customer entirely.

    Finding what is missing

    Because unmatched rows have NULLs on the right side, you can keep only those:

    SELECT c.customer_id, c.email, c.signup_date
    FROM customers AS c
    LEFT JOIN orders AS o ON o.customer_id = c.customer_id
    WHERE o.order_id IS NULL;

    This pattern is called an anti-join: rows in A with no match in B. Analysts use it constantly: customers who never ordered, products that never sold, sessions with no customer, orders with no shipment.

    Test a column that cannot be NULL on a match

    Check the right table’s key (o.order_id) or the join column (o.customer_id), never an optional column. If you wrote WHERE o.coupon_code IS NULL, you would also get every customer whose orders simply had no coupon, which is most of them. A primary key is never NULL in a real match, so its NULL means “no match” and nothing else.

    Other ways to write it

    -- NOT EXISTS: often the clearest, and safe with NULLs
    SELECT c.customer_id, c.email, c.signup_date
    FROM customers AS c
    WHERE NOT EXISTS (
      SELECT 1 FROM orders AS o WHERE o.customer_id = c.customer_id
    );

    NOT EXISTS is covered in chapter 7. Avoid WHERE customer_id NOT IN (SELECT customer_id FROM orders) when the subquery column can contain NULL: a single NULL makes NOT IN return no rows at all.

    RIGHT and FULL joins

    RIGHT JOIN is a LEFT JOIN with the tables swapped. Most teams never use it and write the table they want to keep first. FULL OUTER JOIN keeps unmatched rows from both sides, useful for reconciling two sources (“which orders are in the warehouse system but not in billing, and the reverse”). MySQL does not support FULL OUTER JOIN; you emulate it with a UNION of a LEFT and a RIGHT join.

    Common mistakes

    • Using JOIN and then looking for NULLs. An inner join never produces unmatched rows, so the result is always empty.
    • Counting “customers” after a LEFT JOIN with COUNT(*). Customers with several orders are counted several times. Use COUNT(DISTINCT c.customer_id).