The request

From Daniel Foster, Mobile Product Manager
Your goal
For every customer with segment 'business', return customer_id and app_orders: the number of their orders with channel 'app' (any status). Business customers with no app orders must appear with app_orders = 0.
- Read from the
customerstablenot done yet - Read from the
orderstablenot done yet - Show exactly
customer_idapp_ordersnot done yet
Your query
Loading the editor…
Reference solution
| customer_id | first_name | last_name | city | |
|---|---|---|---|---|
| 1 | Owen | Hudson | owen.hudson@icloud.com | San Francisco |
| 2 | Douglas | Mendoza | dmendoza69@gmail.com | Atlanta |
| 3 | Henry | Brooks | hbrooks@lakesidecafe.com | Los Angeles |
| 4 | Brian | Graham | bgraham@bluecedarhomes.com | Seattle |
Mote checks your result
Press Run. Each row that matches the goal becomes a firefly in your lantern.
What Daniel gets, and why
Tables
Harbor & Pine store data, ready to query.
customers2,018 rows · 9 columns
customer_idintegerfirst_namevarcharlast_namevarcharemailvarcharcityvarcharstatevarcharsignup_datedatesegmentvarcharreferral_sourcevarchar
| customer_id | first_name | last_name | city | state | signup_date | segment | referral_source | |
|---|---|---|---|---|---|---|---|---|
| 1 | Owen | Hudson | owen.hudson@icloud.com | San Francisco | CA | 2022-06-02 | consumer | search |
| 2 | Douglas | Mendoza | dmendoza69@gmail.com | Atlanta | GA | 2022-06-02 | consumer | NULL |
| 3 | Henry | Brooks | hbrooks@lakesidecafe.com | Los Angeles | CA | 2022-06-04 | business | NULL |
| 4 | Brian | Graham | bgraham@bluecedarhomes.com | Seattle | WA | 2022-06-06 | business | |
| 5 | Kyle | Jimenez | kjimenez27@yahoo.com | Indianapolis | IN | 2022-06-07 | consumer | NULL |
orders12,000 rows · 7 columns
order_idintegercustomer_idintegerorder_datetimestampstatusvarcharchannelvarcharshipping_feedecimalcoupon_codevarchar
| order_id | customer_id | order_date | status | channel | shipping_fee | coupon_code |
|---|---|---|---|---|---|---|
| 1001 | 125 | 2023-01-01 20:51:19 | completed | web | 0.00 | NULL |
| 1002 | 156 | 2023-01-02 07:58:46 | completed | web | 0.00 | NULL |
| 1003 | 22 | 2023-01-02 10:25:27 | completed | marketplace | 4.99 | WELCOME10 |
| 1004 | 48 | 2023-01-02 11:21:51 | completed | marketplace | 4.99 | WELCOME10 |
| 1005 | 82 | 2023-01-02 11:43:36 | completed | web | 0.00 | WELCOME10 |
products120 rows · 8 columns
product_idintegernamevarcharcategoryvarcharsubcategoryvarcharunit_pricedecimalunit_costdecimallaunched_ondateis_activeboolean
| product_id | name | category | subcategory | unit_price | unit_cost | launched_on | is_active |
|---|---|---|---|---|---|---|---|
| 101 | Vale Velvet Loveseat | Furniture | Sofas | 1659.00 | NULL | 2023-09-11 | true |
| 102 | Alder Oak Coffee Table | Furniture | Tables | 919.00 | 503.50 | 2024-05-16 | true |
| 103 | Orchard Rattan Dining Chair | Furniture | Chairs | 789.00 | 429.87 | 2023-05-27 | true |
| 104 | Upland Oak Bookcase | Furniture | Storage | 429.00 | 214.70 | 2022-12-20 | true |
| 105 | Avery Leather Bed Frame | Furniture | Beds | 449.00 | 232.70 | 2021-08-31 | true |
order_items30,338 rows · 6 columns
order_item_idintegerorder_idintegerproduct_idintegerquantityintegerunit_pricedecimaldiscount_pctdecimal
| order_item_id | order_id | product_id | quantity | unit_price | discount_pct |
|---|---|---|---|---|---|
| 1 | 1001 | 121 | 9 | 31.99 | 0.00 |
| 2 | 1001 | 154 | 3 | 11.99 | 0.00 |
| 3 | 1002 | 154 | 4 | 11.99 | 0.00 |
| 4 | 1002 | 194 | 1 | 149.00 | 0.00 |
| 5 | 1002 | 193 | 2 | 19.99 | 0.00 |
returns1,673 rows · 5 columns
return_idintegerorder_item_idintegerreturned_ondatereasonvarcharrefund_amountdecimal
| return_id | order_item_id | returned_on | reason | refund_amount |
|---|---|---|---|---|
| 1 | 14 | 2023-01-10 | damaged | 83.69 |
| 2 | 42 | 2023-01-10 | wrong_item | 19.99 |
| 3 | 105 | 2023-01-14 | wrong_item | 10.99 |
| 4 | 24 | 2023-01-16 | changed_mind | 26.99 |
| 5 | 126 | 2023-01-16 | late | 20.99 |
employees60 rows · 8 columns
employee_idintegerfirst_namevarcharlast_namevarchardepartmentvarchartitlevarcharmanager_idintegerhire_datedatesalaryinteger
| employee_id | first_name | last_name | department | title | manager_id | hire_date | salary |
|---|---|---|---|---|---|---|---|
| 1 | Catherine | Hale | Executive | Chief Executive Officer | NULL | 2016-03-01 | 285000 |
| 2 | Robert | Kim | Executive | Chief Operating Officer | 1 | 2017-01-09 | 235000 |
| 3 | Megan | Collins | Sales | Head of Sales | 1 | 2018-04-16 | 172000 |
| 4 | Chloe | Gutierrez | Sales | Account Executive | 3 | 2020-01-21 | 72000 |
| 5 | Frank | Bell | Sales | Account Executive | 3 | 2023-05-21 | 73000 |
web_sessions40,000 rows · 7 columns
session_idintegercustomer_idintegerstarted_attimestampdevicevarcharsourcevarcharpages_viewedintegerconvertedboolean
| session_id | customer_id | started_at | device | source | pages_viewed | converted |
|---|---|---|---|---|---|---|
| 1 | NULL | 2023-01-01 23:02:24 | mobile | paid | 1 | false |
| 2 | 18 | 2023-01-01 15:07:49 | desktop | paid | 1 | false |
| 3 | NULL | 2023-01-01 16:55:46 | desktop | direct | 7 | false |
| 4 | NULL | 2023-01-01 12:43:28 | mobile | organic | 3 | false |
| 5 | NULL | 2023-01-01 13:06:21 | mobile | social | 2 | false |
marketing_spend3,276 rows · 3 columns
spend_datedatechannelvarcharamountdecimal
| spend_date | channel | amount |
|---|---|---|
| 2023-01-01 | paid | 492.99 |
| 2023-01-01 | 37.38 | |
| 2023-01-01 | social | 200.53 |
| 2023-01-02 | paid | 709.13 |
| 2023-01-02 | 64.13 |
The lesson
This is the most common join bug in analytics, and the starter query has it. The core idea: a WHERE condition on the right table of a LEFT JOIN throws away the unmatched rows, so the LEFT JOIN acts like an inner join. Run the starter, then count the business customers: it returns fewer rows than there are business customers.
What goes wrong
SELECT c.customer_id, COUNT(o.order_id) AS app_orders
FROM customers AS c
LEFT JOIN orders AS o ON o.customer_id = c.customer_id
WHERE c.segment = 'business'
AND o.channel = 'app' -- the bug
GROUP BY c.customer_id;
Follow the logical order. The LEFT JOIN runs first and correctly keeps customers with no orders,
with NULLs for every order column. It also keeps customers whose only orders were on the web, one
row per web order. Then WHERE o.channel = 'app' runs. For both groups, o.channel is NULL or
‘web’, so the condition is not true and the rows are removed. The customers Daniel cares most about,
the ones with zero app orders, are exactly the ones that vanish.
A WHERE condition on the right table of a LEFT JOIN turns it into an INNER JOIN.
The fix: filter in ON
Conditions in ON decide which right-side rows match. They never remove left-side rows:
SELECT c.customer_id, COUNT(o.order_id) AS app_orders
FROM customers AS c
LEFT JOIN orders AS o
ON o.customer_id = c.customer_id
AND o.channel = 'app'
WHERE c.segment = 'business'
GROUP BY c.customer_id;
Now each business customer is matched only to their app orders. If there are none, the customer is
kept with NULLs, and COUNT(o.order_id) counts zero non-NULL values, giving 0.
The condition on the left table, c.segment = 'business', correctly stays in WHERE: it is
meant to remove customers. Putting it in ON would instead keep every customer and just fail to
match orders for consumers, so consumers would show up with 0.
| condition about | goes in |
|---|---|
| which left rows to keep | WHERE |
| which right rows count as a match | ON |
COUNT(*) would also be wrong
With the fix in place, try COUNT(*). Customers with no app orders now show 1, because the LEFT JOIN
produced one row for them (full of NULLs). Count a column from the right table instead.
Interview note
“Why did my LEFT JOIN lose rows?” is a staple of SQL interviews and take-home reviews. Explain it in terms of NULLs: the unmatched rows have NULL in the right-side columns, a WHERE comparison with NULL is unknown, and WHERE keeps only true rows. Then give the fix: move the condition into ON, or filter the right table in a subquery before joining.
Lantern lit!
Practised: left joinon vs wherecountzero rows
- Solved
- No hints
- First run
