1. Lighthouse

Level 3 · App orders per business customer

The request

From Daniel Foster, Mobile Product Manager

“We're pitching the app to business accounts. For every business customer, how many orders have they placed in the app? I need the zeros too, they're the target list.”

Your goal

For every customer with segment 'business', return customer_id and app_orders: the number of their orders with channel 'app' (any status). Business customers with no app orders must appear with app_orders = 0.

  • Read from the customers tablenot done yet
  • Read from the orders tablenot done yet
  • Show exactly customer_id app_ordersnot done yet

Your query

SQL

Loading the editor…

    ResultPreview of customers · press Run to see yours
    Preview of customers
    customer_idfirst_namelast_nameemailcity
    1OwenHudsonowen.hudson@icloud.comSan Francisco
    2DouglasMendozadmendoza69@gmail.comAtlanta
    3HenryBrookshbrooks@lakesidecafe.comLos Angeles
    4BrianGrahambgraham@bluecedarhomes.comSeattle

    Mote checks your result

    Press Run. Each row that matches the goal becomes a firefly in your lantern.

    Tables

    Harbor & Pine store data, ready to query.

    customers2,018 rows · 9 columns
    • customer_idinteger
    • first_namevarchar
    • last_namevarchar
    • emailvarchar
    • cityvarchar
    • statevarchar
    • signup_datedate
    • segmentvarchar
    • referral_sourcevarchar
    First 5 rows of customers
    customer_idfirst_namelast_nameemailcitystatesignup_datesegmentreferral_source
    1OwenHudsonowen.hudson@icloud.comSan FranciscoCA2022-06-02consumersearch
    2DouglasMendozadmendoza69@gmail.comAtlantaGA2022-06-02consumerNULL
    3HenryBrookshbrooks@lakesidecafe.comLos AngelesCA2022-06-04businessNULL
    4BrianGrahambgraham@bluecedarhomes.comSeattleWA2022-06-06businesspinterest
    5KyleJimenezkjimenez27@yahoo.comIndianapolisIN2022-06-07consumerNULL
    orders12,000 rows · 7 columns
    • order_idinteger
    • customer_idinteger
    • order_datetimestamp
    • statusvarchar
    • channelvarchar
    • shipping_feedecimal
    • coupon_codevarchar
    First 5 rows of orders
    order_idcustomer_idorder_datestatuschannelshipping_feecoupon_code
    10011252023-01-01 20:51:19completedweb0.00NULL
    10021562023-01-02 07:58:46completedweb0.00NULL
    1003222023-01-02 10:25:27completedmarketplace4.99WELCOME10
    1004482023-01-02 11:21:51completedmarketplace4.99WELCOME10
    1005822023-01-02 11:43:36completedweb0.00WELCOME10
    products120 rows · 8 columns
    • product_idinteger
    • namevarchar
    • categoryvarchar
    • subcategoryvarchar
    • unit_pricedecimal
    • unit_costdecimal
    • launched_ondate
    • is_activeboolean
    First 5 rows of products
    product_idnamecategorysubcategoryunit_priceunit_costlaunched_onis_active
    101Vale Velvet LoveseatFurnitureSofas1659.00NULL2023-09-11true
    102Alder Oak Coffee TableFurnitureTables919.00503.502024-05-16true
    103Orchard Rattan Dining ChairFurnitureChairs789.00429.872023-05-27true
    104Upland Oak BookcaseFurnitureStorage429.00214.702022-12-20true
    105Avery Leather Bed FrameFurnitureBeds449.00232.702021-08-31true
    order_items30,338 rows · 6 columns
    • order_item_idinteger
    • order_idinteger
    • product_idinteger
    • quantityinteger
    • unit_pricedecimal
    • discount_pctdecimal
    First 5 rows of order_items
    order_item_idorder_idproduct_idquantityunit_pricediscount_pct
    11001121931.990.00
    21001154311.990.00
    31002154411.990.00
    410021941149.000.00
    51002193219.990.00
    returns1,673 rows · 5 columns
    • return_idinteger
    • order_item_idinteger
    • returned_ondate
    • reasonvarchar
    • refund_amountdecimal
    First 5 rows of returns
    return_idorder_item_idreturned_onreasonrefund_amount
    1142023-01-10damaged83.69
    2422023-01-10wrong_item19.99
    31052023-01-14wrong_item10.99
    4242023-01-16changed_mind26.99
    51262023-01-16late20.99
    employees60 rows · 8 columns
    • employee_idinteger
    • first_namevarchar
    • last_namevarchar
    • departmentvarchar
    • titlevarchar
    • manager_idinteger
    • hire_datedate
    • salaryinteger
    First 5 rows of employees
    employee_idfirst_namelast_namedepartmenttitlemanager_idhire_datesalary
    1CatherineHaleExecutiveChief Executive OfficerNULL2016-03-01285000
    2RobertKimExecutiveChief Operating Officer12017-01-09235000
    3MeganCollinsSalesHead of Sales12018-04-16172000
    4ChloeGutierrezSalesAccount Executive32020-01-2172000
    5FrankBellSalesAccount Executive32023-05-2173000
    web_sessions40,000 rows · 7 columns
    • session_idinteger
    • customer_idinteger
    • started_attimestamp
    • devicevarchar
    • sourcevarchar
    • pages_viewedinteger
    • convertedboolean
    First 5 rows of web_sessions
    session_idcustomer_idstarted_atdevicesourcepages_viewedconverted
    1NULL2023-01-01 23:02:24mobilepaid1false
    2182023-01-01 15:07:49desktoppaid1false
    3NULL2023-01-01 16:55:46desktopdirect7false
    4NULL2023-01-01 12:43:28mobileorganic3false
    5NULL2023-01-01 13:06:21mobilesocial2false
    marketing_spend3,276 rows · 3 columns
    • spend_datedate
    • channelvarchar
    • amountdecimal
    First 5 rows of marketing_spend
    spend_datechannelamount
    2023-01-01paid492.99
    2023-01-01email37.38
    2023-01-01social200.53
    2023-01-02paid709.13
    2023-01-02email64.13

    The lesson

    This is the most common join bug in analytics, and the starter query has it. The core idea: a WHERE condition on the right table of a LEFT JOIN throws away the unmatched rows, so the LEFT JOIN acts like an inner join. Run the starter, then count the business customers: it returns fewer rows than there are business customers.

    What goes wrong

    SELECT c.customer_id, COUNT(o.order_id) AS app_orders
    FROM customers AS c
    LEFT JOIN orders AS o ON o.customer_id = c.customer_id
    WHERE c.segment = 'business'
      AND o.channel = 'app'          -- the bug
    GROUP BY c.customer_id;

    Follow the logical order. The LEFT JOIN runs first and correctly keeps customers with no orders, with NULLs for every order column. It also keeps customers whose only orders were on the web, one row per web order. Then WHERE o.channel = 'app' runs. For both groups, o.channel is NULL or ‘web’, so the condition is not true and the rows are removed. The customers Daniel cares most about, the ones with zero app orders, are exactly the ones that vanish.

    A WHERE condition on the right table of a LEFT JOIN turns it into an INNER JOIN.

    The fix: filter in ON

    Conditions in ON decide which right-side rows match. They never remove left-side rows:

    SELECT c.customer_id, COUNT(o.order_id) AS app_orders
    FROM customers AS c
    LEFT JOIN orders AS o
      ON o.customer_id = c.customer_id
     AND o.channel = 'app'
    WHERE c.segment = 'business'
    GROUP BY c.customer_id;

    Now each business customer is matched only to their app orders. If there are none, the customer is kept with NULLs, and COUNT(o.order_id) counts zero non-NULL values, giving 0.

    The condition on the left table, c.segment = 'business', correctly stays in WHERE: it is meant to remove customers. Putting it in ON would instead keep every customer and just fail to match orders for consumers, so consumers would show up with 0.

    condition about goes in
    which left rows to keep WHERE
    which right rows count as a match ON

    COUNT(*) would also be wrong

    With the fix in place, try COUNT(*). Customers with no app orders now show 1, because the LEFT JOIN produced one row for them (full of NULLs). Count a column from the right table instead.

    Interview note

    “Why did my LEFT JOIN lose rows?” is a staple of SQL interviews and take-home reviews. Explain it in terms of NULLs: the unmatched rows have NULL in the right-side columns, a WHERE comparison with NULL is unknown, and WHERE keeps only true rows. Then give the fix: move the condition into ON, or filter the right table in a subquery before joining.