1. Lighthouse

Level 5 · Who reports to whom

The request

From Nicole Bennett, HR Business Partner

“I'm updating the org chart. Can you give me every employee with their title and their manager's full name? Our CEO has no manager, so leave that blank for her.”

Your goal

From employees, return employee_id, employee_name (first_name, a space, last_name), title and manager_name (the manager's first_name, a space, last_name). Include every employee; manager_name is NULL for the employee with no manager.

  • Read from the employees tablenot done yet
  • Show exactly employee_id employee_name title manager_namenot done yet
  • 60 rowsnot done yet

Your query

SQL

Loading the editor…

    ResultPreview of employees · press Run to see yours
    Preview of employees
    employee_idfirst_namelast_namedepartmenttitle
    1CatherineHaleExecutiveChief Executive Officer
    2RobertKimExecutiveChief Operating Officer
    3MeganCollinsSalesHead of Sales
    4ChloeGutierrezSalesAccount Executive

    Mote checks your result

    Press Run. Each row that matches the goal becomes a firefly in your lantern.

    Tables

    Harbor & Pine store data, ready to query.

    employees60 rows · 8 columns
    • employee_idinteger
    • first_namevarchar
    • last_namevarchar
    • departmentvarchar
    • titlevarchar
    • manager_idinteger
    • hire_datedate
    • salaryinteger
    First 5 rows of employees
    employee_idfirst_namelast_namedepartmenttitlemanager_idhire_datesalary
    1CatherineHaleExecutiveChief Executive OfficerNULL2016-03-01285000
    2RobertKimExecutiveChief Operating Officer12017-01-09235000
    3MeganCollinsSalesHead of Sales12018-04-16172000
    4ChloeGutierrezSalesAccount Executive32020-01-2172000
    5FrankBellSalesAccount Executive32023-05-2173000
    customers2,018 rows · 9 columns
    • customer_idinteger
    • first_namevarchar
    • last_namevarchar
    • emailvarchar
    • cityvarchar
    • statevarchar
    • signup_datedate
    • segmentvarchar
    • referral_sourcevarchar
    First 5 rows of customers
    customer_idfirst_namelast_nameemailcitystatesignup_datesegmentreferral_source
    1OwenHudsonowen.hudson@icloud.comSan FranciscoCA2022-06-02consumersearch
    2DouglasMendozadmendoza69@gmail.comAtlantaGA2022-06-02consumerNULL
    3HenryBrookshbrooks@lakesidecafe.comLos AngelesCA2022-06-04businessNULL
    4BrianGrahambgraham@bluecedarhomes.comSeattleWA2022-06-06businesspinterest
    5KyleJimenezkjimenez27@yahoo.comIndianapolisIN2022-06-07consumerNULL
    products120 rows · 8 columns
    • product_idinteger
    • namevarchar
    • categoryvarchar
    • subcategoryvarchar
    • unit_pricedecimal
    • unit_costdecimal
    • launched_ondate
    • is_activeboolean
    First 5 rows of products
    product_idnamecategorysubcategoryunit_priceunit_costlaunched_onis_active
    101Vale Velvet LoveseatFurnitureSofas1659.00NULL2023-09-11true
    102Alder Oak Coffee TableFurnitureTables919.00503.502024-05-16true
    103Orchard Rattan Dining ChairFurnitureChairs789.00429.872023-05-27true
    104Upland Oak BookcaseFurnitureStorage429.00214.702022-12-20true
    105Avery Leather Bed FrameFurnitureBeds449.00232.702021-08-31true
    orders12,000 rows · 7 columns
    • order_idinteger
    • customer_idinteger
    • order_datetimestamp
    • statusvarchar
    • channelvarchar
    • shipping_feedecimal
    • coupon_codevarchar
    First 5 rows of orders
    order_idcustomer_idorder_datestatuschannelshipping_feecoupon_code
    10011252023-01-01 20:51:19completedweb0.00NULL
    10021562023-01-02 07:58:46completedweb0.00NULL
    1003222023-01-02 10:25:27completedmarketplace4.99WELCOME10
    1004482023-01-02 11:21:51completedmarketplace4.99WELCOME10
    1005822023-01-02 11:43:36completedweb0.00WELCOME10
    order_items30,338 rows · 6 columns
    • order_item_idinteger
    • order_idinteger
    • product_idinteger
    • quantityinteger
    • unit_pricedecimal
    • discount_pctdecimal
    First 5 rows of order_items
    order_item_idorder_idproduct_idquantityunit_pricediscount_pct
    11001121931.990.00
    21001154311.990.00
    31002154411.990.00
    410021941149.000.00
    51002193219.990.00
    returns1,673 rows · 5 columns
    • return_idinteger
    • order_item_idinteger
    • returned_ondate
    • reasonvarchar
    • refund_amountdecimal
    First 5 rows of returns
    return_idorder_item_idreturned_onreasonrefund_amount
    1142023-01-10damaged83.69
    2422023-01-10wrong_item19.99
    31052023-01-14wrong_item10.99
    4242023-01-16changed_mind26.99
    51262023-01-16late20.99
    web_sessions40,000 rows · 7 columns
    • session_idinteger
    • customer_idinteger
    • started_attimestamp
    • devicevarchar
    • sourcevarchar
    • pages_viewedinteger
    • convertedboolean
    First 5 rows of web_sessions
    session_idcustomer_idstarted_atdevicesourcepages_viewedconverted
    1NULL2023-01-01 23:02:24mobilepaid1false
    2182023-01-01 15:07:49desktoppaid1false
    3NULL2023-01-01 16:55:46desktopdirect7false
    4NULL2023-01-01 12:43:28mobileorganic3false
    5NULL2023-01-01 13:06:21mobilesocial2false
    marketing_spend3,276 rows · 3 columns
    • spend_datedate
    • channelvarchar
    • amountdecimal
    First 5 rows of marketing_spend
    spend_datechannelamount
    2023-01-01paid492.99
    2023-01-01email37.38
    2023-01-01social200.53
    2023-01-02paid709.13
    2023-01-02email64.13

    The lesson

    A self join joins a table to itself. It is how you work with hierarchies stored in one table: employees and managers, categories and parent categories, referrals between customers.

    In employees, manager_id holds the employee_id of each person’s manager. To show the manager’s name, you need a second copy of the table playing the role of “manager”:

    SELECT
      e.first_name AS employee,
      m.first_name AS manager
    FROM employees AS e
    LEFT JOIN employees AS m ON m.employee_id = e.manager_id;

    The aliases are not optional here. e and m are two roles for the same table, and every column must say which role it comes from.

    Why LEFT JOIN

    The CEO has manager_id NULL. With an inner join, NULL = m.employee_id never matches, and the CEO disappears from the org chart. LEFT JOIN keeps her, with NULL manager columns. In any hierarchy, the top of the tree has no parent, so self joins are almost always LEFT joins.

    Concatenating text

    || joins strings in Postgres, DuckDB, SQLite, Oracle and Snowflake:

    e.first_name || ' ' || e.last_name AS employee_name

    MySQL uses CONCAT(first_name, ' ', last_name) (in MySQL, || means OR unless a SQL mode is set). BigQuery supports both || and CONCAT. CONCAT also exists in Postgres and DuckDB, so it is the most portable choice.

    They differ on NULLs: 'Hale' || NULL is NULL, while CONCAT('Hale', NULL) returns 'Hale' in Postgres and DuckDB (and NULL in MySQL). For the CEO, m.first_name || ' ' || m.last_name is NULL, which is what Nicole asked for. CONCAT would return a single space, which looks blank but is not NULL and would break a later IS NULL check.

    Going further up the tree

    One self join gives one level. “Manager’s manager” needs a second join to a third alias:

    LEFT JOIN employees AS m  ON m.employee_id  = e.manager_id
    LEFT JOIN employees AS mm ON mm.employee_id = m.manager_id

    For a hierarchy of unknown depth, Postgres, DuckDB, MySQL 8 and BigQuery support recursive CTEs (WITH RECURSIVE), which walk the tree until it ends. That is an advanced interview topic and worth knowing exists.

    Common uses for analysts

    • Headcount and salary by manager (join, then group by the manager’s name).
    • Finding employees who earn more than their manager, a well-known interview question: WHERE e.salary > m.salary.
    • Comparing rows within a table, such as orders by the same customer, although window functions (chapter 8) usually do that more simply.